Projectile kinematics sticker for me

AI Thread Summary
To calculate the velocity of an object thrown horizontally at an initial speed of 24 m/s after 4 seconds, one must consider both horizontal and vertical motion. The horizontal velocity remains constant at 24 m/s, while the vertical velocity can be calculated using the formula for free fall under gravity, which is approximately 9.81 m/s². After 4 seconds, the vertical velocity would be 39.24 m/s downward. The resultant velocity can be found using the Pythagorean theorem, combining the horizontal and vertical components. This discussion highlights the importance of understanding both horizontal and vertical motion in projectile kinematics.
triggerhorse
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I know that an object is thrown at a certain initial horizontal speed (m/s). I need to calculate the object's velocity (magnitude and direction) after a certain amount of time (seconds.) How would I do this? What formulas would I use? The actual question is: a calculator thrown at initial horz speed of 24m/s and calculate velocity(mag &direction) after 4 seconds.
 
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hi triggerhorse, welcome to PF

generally you have to give an attempt at a solution and people will offer help...

I would start by writing the forces on the calculator
 
Kinematic equations.. There is no acceleration in this case.
 
based on the question though i doubt it, i'd assume it experiences gravity... triggerhorse can you elaborate?
 
lanedance said:
based on the question though i doubt it, i'd assume it experiences gravity... triggerhorse can you elaborate?

But only horizontal velocity is given, I presume its not projectile motion.
Don't think this much data is enough to describe projectile motion.
 
Thanks for your help so far. I am going to get help at school today.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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