I have my average d(adsbygoogle = window.adsbygoogle || []).push({}); _{y}, but the machine that launched the projectile was placed on the table. So d_{y}in the equation 1/2at^{2}+v_{yi}-d_{y}=0 would be the height from the ground to the table or from the table to the highest point of the parabola? Pick one please. Red or Black for d_{y}? Can you explain why?

From there, I can solve by using V_{yf}^{2}=V_{yi}^{2}+2ad_{y}for V_{yi}^{2}. Then I use 1/2at^{2}+v_{yi}-d_{y}=0 in the form of the quadratic formula but the derivation of x. Then I solve for x (which is t in the physics equation) and plug it into d_{x}=v_{x}t.

This lab is one wher we work out the d_{x}and we experiment to see if the experiment proves our hypothesis. Air resistance is not factored in.

Thank you for any help.

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# Homework Help: Projectile launched at an angle; dy?

Can you offer guidance or do you also need help?

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