Projectile launched at an angle; dy?

[Shiz]

I have my average d_y, but the machine that launched the projectile was placed on the table. So d_y in the equation 1/2at²+v_yi-d_y=0 would be the height from the ground to the table or from the table to the highest point of the parabola? Pick one please. Red or Black for d_y? Can you explain why?

From there, I can solve by using V_yf²=V_yi²+2ad_y for V_yi². Then I use 1/2at²+v_yi-d_y=0 in the form of the quadratic formula but the derivation of x. Then I solve for x (which is t in the physics equation) and plug it into d_x=v_xt.

This lab is one wher we work out the d_x and we experiment to see if the experiment proves our hypothesis. Air resistance is not factored in.

Thank you for any help.

 

[jbsteele]

In this case, dy should be the height from the ground to the table. This is because the equation 1/2at2+vyi-dy=0 is a representation of the equation for the vertical displacement of a projectile, where dy represents the starting displacement from the ground. Since the machine was placed on the table, dy should represent the height from the ground to the table.

 

[thomate1]

I would like to clarify that dy in the equation 1/2at2+vyi-dy=0 represents the vertical displacement of the projectile from its initial position. In this case, if the machine launching the projectile was placed on a table, then dy would be the height from the table to the highest point of the parabola. This is because the initial position of the projectile is considered to be at the same level as the machine.

In terms of choosing between red or black for dy, it would depend on the color-coding system used in the experiment. It is important to be consistent and clear with the labeling of variables in any scientific experiment.

Regarding the method of solving for Vyi2 and x, the equations you have mentioned seem to be correct and appropriate for this experiment. However, as a scientist, I would also suggest considering the effect of air resistance on the projectile's motion, as it can significantly affect the accuracy of the results. Perhaps, conducting the experiment in a controlled environment with minimal air resistance would be more ideal.

Overall, the key to a successful experiment is to carefully plan and design it, considering all factors that may affect the results. And as always, it is important to analyze and interpret the data accurately to validate or disprove the hypothesis.