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Projectile launched at an angle; dy?

  1. Dec 9, 2008 #1
    I have my average dy, but the machine that launched the projectile was placed on the table. So dy in the equation 1/2at2+vyi-dy=0 would be the height from the ground to the table or from the table to the highest point of the parabola? Pick one please. Red or Black for dy? Can you explain why?

    From there, I can solve by using Vyf2=Vyi2+2ady for Vyi2. Then I use 1/2at2+vyi-dy=0 in the form of the quadratic formula but the derivation of x. Then I solve for x (which is t in the physics equation) and plug it into dx=vxt.

    This lab is one wher we work out the dx and we experiment to see if the experiment proves our hypothesis. Air resistance is not factored in.

    Thank you for any help.
     

    Attached Files:

  2. jcsd
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