Projectile Motion airplane engine question

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An airplane flying horizontally at 1000 km/h (280 m/s) experiences an engine detaching, which takes 30 seconds to hit the ground. The calculations show that the airplane is approximately 4.0 km high, derived from the equation d = 4.9t², where t is the time in seconds. The horizontal distance the engine travels while falling is calculated as 8400 m, using the formula distance = speed x time. The engine's horizontal velocity matches that of the airplane at the moment of detachment, meaning it will land 8400 m away from the point directly below where it fell off. The confusion primarily stems from applying the correct kinematic equations for both vertical and horizontal motion.
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1. You're in an airplane that flies horizontally with speed 1000 km/h (280 m/s) when an engine falls off. Neglecting air resistance, assume it takes 30 s for the engine to hit the ground.

a. Show that the airplane is 4.0 km high.

b. Show that the horizontal distance that the aircraft engine falls is 8400 m

c. If the airplane somehow continues to fly as if nothing had happened, where is the engine relative to the airplane at the moment the engine hits the ground?




I am confused! I need help with this problem and the steps to formulate the solutions..
 
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When the engine detaches from the plane, its velocity in the horizontal direction is the velocity of the plane. But its velocity in the vertical direction id zero.
So what is the kinematic equation which relates the displacement, initial velocity, acceleration and time?
 
d=5t² ? I am just really confused about this question. I have been studying physics for several hours now and my brain is just not comprehending this for some reason when I know it should...
 
I understand the "c" part of the problem but I am still confused with "a" and "b" I know the equation d=5t² but there needs to be a further extension of this equation. I am just stuck with how I would show parts "a" and "b" with the question that it is asking me..
 
Ok I figured out for part "b" I did not need a simple equation...I really am brain dead right now! lol...280 m/s x 30 s = 8400 m

For part "a" I plugged into the equation for "d=5t² = 4 km= 5*30s²" but I don't know if I am correct..
 
d = 4.9*30^2 = 4481 m =~ 4 km.

Horizontal distance = 280*30 = ?
 
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