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## Main Question or Discussion Point

A rifle is fired at an angle of 25° below the horizontal with an initial velocity of 400 m/s from the top of a cliff 60.0m high. How far from the base of the cliff does the bullet land?

This is what I did, but i'm not sure if its right:

y-component→ v=400sin(25°) ∴v=169.05

x-component→ v=400cos(25°)∴v=362.52

I found the time by doing: t= 60/169.05∴t= .355s

From here I multiplied the time with the x-component to find the distance(X) : X=.355(362.52)∴ X=128.69m

Is this right???

If not please help me.

This is what I did, but i'm not sure if its right:

y-component→ v=400sin(25°) ∴v=169.05

x-component→ v=400cos(25°)∴v=362.52

I found the time by doing: t= 60/169.05∴t= .355s

From here I multiplied the time with the x-component to find the distance(X) : X=.355(362.52)∴ X=128.69m

Is this right???

If not please help me.