Projectile Motion Equation: Calculating Height from Initial Velocity and Time

AI Thread Summary
The discussion centers on calculating the height from which a ball is thrown, given its initial velocity and time of flight. The initial velocity is 7.90 m/s at a 21.9-degree angle below the horizontal, and it strikes the ground after 2.95 seconds. The equation used for the calculation is y = y0 + vy0t - 1/2gt^2, leading to an initial height of 33.95 meters. Participants emphasize the importance of consistent sign conventions for direction in calculations, particularly regarding the assignment of positive and negative values for height and acceleration. Correcting these signs is crucial for accurate results in projectile motion problems.
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Homework Statement


A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 7.90m/s at an angle of 21.9deg below the horizontal. It strikes the ground 2.95s later.
Calculate the height from which the ball was thrown.

Homework Equations

The Attempt at a Solution


y=y0+vy0t- 1/2gt^2
vy0=sin21.9 deg*7.9m/s=2.9466m/s
0=y0+2.9466m/s(2.95s)-(1/2)(9.8m/s^2)(2.95s)^2
y0=33.95m
could anybody tell me where have done wrong?
 
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Check your signs.
 
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KevinFan said:

Homework Statement


A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 7.90m/s at an angle of 21.9deg below the horizontal. It strikes the ground 2.95s later.
Calculate the height from which the ball was thrown.

Homework Equations

The Attempt at a Solution


y=y0+vy0t- 1/2gt^2
vy0=sin21.9 deg*7.9m/s=2.9466m/s
0=y0+2.9466m/s(2.95s)-(1/2)(9.8m/s^2)(2.95s)^2
y0=33.95m
could anybody tell me where have done wrong?
You need to be consistent about how you assign the positive directions. If you want positive to be up, what is the sign on y0? If you want positive to be down, what is the sign on the acceleration?
 
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Bystander said:
Check your signs.
Thank you:)
 
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