1. The problem statement, all variables and given/known data A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 7.90m/s at an angle of 21.9deg below the horizontal. It strikes the ground 2.95s later. Calculate the height from which the ball was thrown. 2. Relevant equations 3. The attempt at a solution y=y0+vy0t- 1/2gt^2 vy0=sin21.9 deg*7.9m/s=2.9466m/s 0=y0+2.9466m/s(2.95s)-(1/2)(9.8m/s^2)(2.95s)^2 y0=33.95m could anybody tell me where have done wrong???