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## Homework Statement

A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 7.90m/s at an angle of 21.9deg below the horizontal. It strikes the ground 2.95s later.

Calculate the height from which the ball was thrown.

## Homework Equations

## The Attempt at a Solution

y=y0+vy0t- 1/2gt^2

vy0=sin21.9 deg*7.9m/s=2.9466m/s

0=y0+2.9466m/s(2.95s)-(1/2)(9.8m/s^2)(2.95s)^2

y0=33.95m

could anybody tell me where have done wrong???