Projectile Motion, Find initial velocity knowing x & y dist and time.

AI Thread Summary
A football player kicks a ball with a flight time of 4.5 seconds, landing 45.7 meters away from a height of 1.52 meters. The problem involves determining the initial velocity's magnitude and direction using projectile motion equations. Initially, the solver struggled to find the angle needed for calculations, considering methods like using the tangent function and maximum height. Ultimately, they resolved the issue by expressing the equations in terms of initial velocity, calculating the launch angle as 64.9 degrees, and determining the initial velocity to be 24 m/s. The discussion highlights the importance of understanding the relationship between angle and initial velocity in projectile motion problems.
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Homework Statement


A football player punts the football so that it will have a time of flight = 4.5s and land 45.7m away. The ball leaves the player's foot 1.52 m above ground.

What is initial velocity? (Magnitude and direction)


Homework Equations



x-x_0 = v_0 * cosθ * t
y-y_0 = v_0 * sinθ * t - 1/2 *g*t^2

v_y = v_0 * sinθ - g*t
v_y^2 = (v_0*sinθ)^2 - 2g(y-y_0)

The Attempt at a Solution



I'm stumped. I can do projectile motion questions, but everytime I have to find initial velocity, I never wind up with the correct answer.

All of the above involve knowing the angle.

I thought maybe θ = tan-1(y/x) but that gives me the wrong angle since that's the angle if the ball was thrown to the ground instead of kicked.

I thought maybe finding the max y height (setting v_y = 0) to solve for angle, but that also involves knowing the angle already.

Help?

Any tips on solving initial velocity questions? I always get stumped on these type. Sigh.
 
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AHAH!

I figured it out :)

Two equations, two unknowns. I solved in terms of v_0, then used that to find my angle (64.9 degrees), then substituted that angle into my horizontal distance formula to find the initial velocity = 24m/s

I feel somewhat silly for having such a hard time with this :/
 
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