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## Homework Statement

Brett bowls a cricket ball at 144km/h. He releases it at 6 degrees below the horizontal from a height of 2.4m.

How far down the pitch does the ball land?

Here is a bad picture of it. http://img822.imageshack.us/i/physics.png/

## Homework Equations

## The Attempt at a Solution

I know I have to change km/h to m/s

So, 144km/h = 40m/s

Horizontal Component = 40 cos (6) = 39.72 m/s

Vertical Component = 40 sin (6) = 4.18 m/s

Here is a pic of it all together.

http://img80.imageshack.us/img80/556/physics3.png [Broken]

Now I have no idea where to go from here. Can some guide me on the next step? or If I have done anything wrong.

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Also I do have another question, which isn't on the subject but I think it has a quick answer.

A parcel is dropped from an aeroplane to a boat at sea. The plane is flying at a speed of 100m/s at a fixed altitude of 120m above sea level.

From what time the moment that it is released, does it take for the parcel to hit the water?

http://www.scientificpsychic.com/mind/lean1.html

Theres how to work it out. But I don't understand how we got from

distance = 1/2 × acceleration × time2 + intial speed × time

to

time2 = (2 × distance) / acceleration

How did the 2 x come in?

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