Projectile Motion: How Far Will a Seed Travel at a Given Angle and Velocity?

AI Thread Summary
To determine how far a seed travels when ejected from a height of 1.4 m at a velocity of 3.0 m/s at a 20-degree angle below the horizontal, the velocity must be broken into x and y components. The x-component is calculated as 3cos(20), while the y-component is 3sin(20). The quadratic equation is used to find the time of flight, with the equation set up as 0 = 1/2(9.8)t^2 + 3sin(20)t + 1.4. The total horizontal distance can then be calculated by multiplying the x-component by the overall time. This approach provides a systematic method to solve the projectile motion problem.
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Homework Statement



You spit a seed from a height of 1.4 m above the ground, at a velocity of 3.0 m/s at an angle of 20 below the horizontal. How far from you does it land?

Homework Equations



vxo= vo(cos20)
vyo=vo(sin20

The Attempt at a Solution



not sure where to start..
 
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Break the overall velocity into x and y components.

x direction <=> 3cos(20) = ?

y direction <=> 3sin(20) = ?

Use quadratic equation to find the overall time.

0= 1/2 (9.8)t^2 ( value for a) + 3sin(20)t (value for b) + 1.4 (value for c)

Total distance traveled can be calculated by ( 3cos(20) x ( overall time))

P.S. Next time , at least try to initiate the attempt.

Good luck.
 
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