Projectile Motion (in a vaccum)

AI Thread Summary
The discussion addresses a problem related to projectile motion in a vacuum, specifically the relationship between time of flight, maximum height, and initial velocity. The user highlights a confusion regarding the calculation of maximum height time, which should be half of the total time until impact. A correction is noted about a missing cosine term in the formula for velocity. The user expresses gratitude for assistance in resolving the issue. The conversation emphasizes the importance of accurately applying trigonometric functions in projectile motion equations.
RogerDodgr
Messages
20
Reaction score
0
issue resolved; thanks dick

Given are listed in photo:
t_f=time final (at impact)
y_max = max height
v_o = initial velocity
final height = initial height = 0
x_f =D = final distance

I am having a problem with this because I know max height time must be half of final time at impact (zero height):
http://www.sudokupuzzles.net/blstc.gif
 
Last edited by a moderator:
Physics news on Phys.org
You lost a cos(alpha) around the middle of the page. v0^2=16*D/(cos(alpha)^2*tan(alpha)). Note the squared on the cos(alpha).
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top