Projectile motion (magnitude and direction)

AI Thread Summary
A projectile is launched at 45 m/s at a 40-degree angle, and the goal is to determine its velocity after 4 seconds. The vertical and horizontal components of the initial velocity are calculated using trigonometric functions. The vertical velocity changes due to gravity, while the horizontal velocity remains constant. The final velocity is found using the kinematics equation and the resultant vector formula. The discussion concludes with confirmation of understanding the concepts involved in the calculations.
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Homework Statement


A projectile is fired at a speed of 45 m/s at an angle of 40 degrees above horizontal. Determine the magnitude and direction of its velocity 4 seconds later.


Homework Equations


ax=0 ay=-g


The Attempt at a Solution

 
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find the vy and the vx after 4 seconds and find the resultant vector.
 
needlottahelp said:
find the vy and the vx after 4 seconds and find the resultant vector.

yeah i don't get how to do that though
 
oh hahah ok well
Given: vi= 45 m/s and t = 4
so vyi = sin (40) vi and vxi = cos (40) vi

and to find the speed in four seconds you use the kinematics equation
vyf = vyi + (ay) (t) and velocity in the horizontal remains constant since ax = 0

find those to values and vf = sqrt ( vyf^2 + vxf ^2)

Do you understand it? if not I'll try to explain it a bit more
 
yeah i got it thanks
 
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