Projectile motion of a rabbit

[wallace13]

When chasing a hare along a flat stretch of land, a greyhound leaps into the air at a speed of 9.9 m/s, at an angle 27 degrees above the horizontal

Vf= Viy + at
displacement= Vyt + .5at squared

0= 4.95 (y component for velocity) + 9.81t
t= .504
y= 4.95x.504 + .5x9.81x.504 squared
y displacement= 3.78

using tan 27= 3.745/x
x displacement= 7.33

multiplied by 2 = 14.66

 

[LowlyPion]

What would the question be?

 

[thomate1]

meters

Thank you for sharing this information about the projectile motion of a rabbit. It is interesting to consider the physics of a greyhound chasing a hare. Based on the given information, the greyhound's initial velocity is 9.9 m/s at an angle of 27 degrees above the horizontal. Using the equations for projectile motion, we can calculate the displacement of the greyhound in both the vertical and horizontal directions. The time it takes for the greyhound to reach the peak of its jump can be found by setting the equation for vertical velocity equal to 0. We can then use this time to calculate the vertical displacement. The horizontal displacement can be found using the given angle and the tangent function. Multiplying this by 2 gives us the total displacement of the greyhound, which is approximately 14.66 meters. This information can help us better understand the dynamics of a greyhound's leap when chasing a hare.