Projectile motion of an arrow to an apple

AI Thread Summary
To determine the launch angle for William Tell's arrow, the equations of projectile motion are applied, using an initial speed of 55 m/s and a horizontal distance of 25 m. The horizontal motion is described by the equation x = v₀cos(θ) * t, while the vertical motion is governed by y = v₀sin(θ) * t - (1/2)gt². Since the arrow and apple start at the same height, the vertical position returns to zero, leading to the conclusion that y = 0. The challenge lies in finding the time variable, t, which can be derived from the equations. By solving the two equations simultaneously, both the time and launch angle can be determined.
ornitho
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im having a very difficult time with this question:

William Tell is said to have shot an apple off his son's head with an arrow. If the arrow was shot with an initial speed of 55m/s and the boy was 25m away, at what launch angle did William aim the arrow? The arrow and apple are initially at the same height above the ground.
 
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x = v_{0}\cos \theta \; t
y = v_{0}\sin \theta\; t -\frac{1}{2}gt^{2}

v_{0} = 55So you have:

25 = 55\cos \theta \; t
0 = 55\sin \theta\; t - 5t^{2}
 
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I do not have time value though :(
 
y = 0 wouldn't it, as it is returning to the initial y position, but i still do not understand how I am supposed to find t
 
The maximum altitude occurs at t = \frac{v_{0}\sin\theta}{g}.

The maximum altitude is: \frac{v_{0}^{2}}{2g}\sin^{2}\theta
 
ornitho said:
y = 0 wouldn't it, as it is returning to the initial y position, but i still do not understand how I am supposed to find t

That's right! now if you understand courtrigrad's earlier equations, for velocity and position, you have two equations, and two unknowns (t and the angle, theta). You can then solve the set of equations for both unknowns.
 
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