Projectile Motion on Earth and the Moon: Calculating Distance and Acceleration

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To calculate how far a baseball thrown 40 meters on Earth would travel on the Moon, one can use kinematic equations, adjusting for the Moon's gravity, which is one-sixth that of Earth's. The initial velocity should be considered at the moment of the throw, not at rest, as the ball is in motion. For the second question, the acceleration due to gravity does change slightly at 1000 meters above Earth's surface, but the difference is minimal for basic calculations. The approach involves determining the time the ball remains in the air and using that to find the distance traveled. Understanding these principles is crucial for accurately solving projectile motion problems in different gravitational fields.
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Projectiles- Physics11.
This is part of my lab, and i really can't figure this out:rolleyes:
So I need some help .,


Here are the questions ::

*Assume you can throw a baseball 40 meters on the Earth's surface.How far could you throw that same ball on the surface of the moon, where the acceleration of gravity is one-sixth what it is at the surface of the earth??

*AND will the acceleration due to gravity be different at 1000 meters above the surface of the Earth?

please i need help:blushing:
Thank you sooo much..
 
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Well for the first part, you can use the kinematic equations to determine how fast you actually threw the ball and plug this velocity into a new kinematic equation with hte moon's gravity in place of the earth.
 
Kinematics Equations?

Which question should i use?
Would i consider Initial Velocity at 0m/s
or the Final Velocity at 0m/s?
If the case is when you throw the ball ?
Thank you
 
Which question should i use?
Would i consider Initial Velocity at 0m/s
or the Final Velocity at 0m/s?
If the case is when you throw the ball ?
Thank you
 
The initial velocity at 0m/s? You mean x=0. Use x=0 i suppose because on a level surface with no friction, it will have the same speed at the end and at the beginning. You do this for the case when the ball is thrown on earth.
 
I don't see any other way to help than to show how I would approach this. Gravity only determines the time the ball remains in the air:

s = v_h*t
t = (v_v-u_v)/g

Go from here.
 
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