Projectile motion question (baseball problem)

AI Thread Summary
The problem involves calculating the initial speed of a baseball hit at an angle of 30.5° from a height of 1.320 m, clearing a fence 94.0 m away and 11.20 m tall. The initial equations used included horizontal and vertical motion formulas, but there were errors in applying the vertical motion equation. The diameter of the baseball should be considered when determining the height clearance, adjusting the vertical distance to 9.92 m. After recalculating, one participant suggested an initial speed of 35.99 m/s, indicating a potential math error in previous attempts. Accurate calculations and proper use of trigonometric functions are crucial for solving projectile motion problems.
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Homework Statement



The center of a baseball of diameter 8.20 cm is 1.320 m vertically above the plate when it is hit. The blast sends it off at an angle of 30.5° above the horizontal with an unknown initial speed. The outfield fence is 94.0 m away and 11.20 m tall: the ball just clears it. Ignoring aerodynamic effects, what was the initial speed of the baseball?

Homework Equations



-d=vt for the x direction
-any free fall equation for the y direction

The Attempt at a Solution



dx= 94.0m dy= 9.88m (subtracted the height in which the ball was hit at)
Vx= vcos(30.5 Viy=?
t= 94.0/vcos(30.5 a= -9.8m.s^2

d=vit+1/2at^2
9.88=vi(94.0/vcos(30.5)-4.9(94.0/vcos(30.5)^2
v^2(-99.22)= -58323.769
v^2= 5884.13
v=76.7m/s

where am i going wrong in this problem? help will be greatly appreciated, thanks!
 
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You have Vx=vcostheta; how about Viy=vsintheta? Looks like you have missed that.
 
thanks for the reply. do i add the diameter of the ball to when it clears the fence too? I'm pretty bad with word problems.
 
boomer77 said:
thanks for the reply. do i add the diameter of the ball to when it clears the fence too? I'm pretty bad with word problems.
i guess to be accurate to 2 places after the decimal point, you'd have to consider the ball diameter, that is, add half its diameter to the y height (y = 9.88 + 0.04 = 9.92) for what it may be worth.
 
i'm still getting this problem wrong so my equation in the y direction would be

9.92=vsin(30.5(94/vcos(30.5)-4.9(94/vcos(30.5)^2

i come up with the answer of 3.88 m/s but my problem set says it's wrong

should i be doing something different?
 
boomer77 said:
i'm still getting this problem wrong so my equation in the y direction would be

9.92=vsin(30.5(94/vcos(30.5)-4.9(94/vcos(30.5)^2

i come up with the answer of 3.88 m/s but my problem set says it's wrong

should i be doing something different?
Looks like the correct approach; I'll check your numbers in a bit...I've got to pick up a take out order for the family..
 
boomer77 said:
i'm still getting this problem wrong so my equation in the y direction would be

9.92=vsin(30.5)[/color](94/vcos(30.5))[/color] - 4.9(94/vcos(30.5))[/color]^2

i come up with the answer of 3.88 m/s but my problem set says it's wrong

should i be doing something different?
Looks like a math error..I get V = 35.99m/s. Check your parentheses..check calculator set to degrees and not radians..
 
thank you very much for the help!
 
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