- #1
JonathanSnow
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[SOLVED] Projectile Motion Question
a swimmer moving at 1.80m/s dives off a pier and hits the water .80 m from the edge of the pier how high is the pier above the water
Vx=change X /change Time
change Y = Vyi . change Time +1/2 a . (change time)^2
i found time with the Vx formula to be .44m/s
then i punched it into the change Y formula to get the height of the pier as 0.94 m
im just wondering if i approached it right and by change i mean the displacement triangle i just don't know how to make the symbol sorry
thanks ahead of time
Homework Statement
a swimmer moving at 1.80m/s dives off a pier and hits the water .80 m from the edge of the pier how high is the pier above the water
Homework Equations
Vx=change X /change Time
change Y = Vyi . change Time +1/2 a . (change time)^2
The Attempt at a Solution
i found time with the Vx formula to be .44m/s
then i punched it into the change Y formula to get the height of the pier as 0.94 m
im just wondering if i approached it right and by change i mean the displacement triangle i just don't know how to make the symbol sorry
thanks ahead of time