(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An arrow is shot at 42 degrees from the horizontal to strike a target that is 53 meters away and at the same elevation as the archer. What is the initial velocity?

2. Relevant equations

I'm not sure which equation(s) is/are needed so I'll list all the ones I can...

(Vix)=(CosX)

x=(Vix)(t)

(Vxf)=(Vxi)

(-Vi)(SinX) = (Vi)(SinX) + (g)(t)

(-2Vfy)=(g)(t)

(Vfy)^2=(Viy)^2 + 2(g)(y)

g=-9.81 m/s

3. The attempt at a solution

I don't know how to solve it. All the information you are given is theta = 42 and the X distance is 53 m, I don't see how you can use any of those equations to solve for anything with only those two pieces of information.

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# Homework Help: Projectile Motion (shooting an arrow)

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