1. The problem statement, all variables and given/known data An arrow is shot at 42 degrees from the horizontal to strike a target that is 53 meters away and at the same elevation as the archer. What is the initial velocity? 2. Relevant equations I'm not sure which equation(s) is/are needed so I'll list all the ones I can... (Vix)=(CosX) x=(Vix)(t) (Vxf)=(Vxi) (-Vi)(SinX) = (Vi)(SinX) + (g)(t) (-2Vfy)=(g)(t) (Vfy)^2=(Viy)^2 + 2(g)(y) g=-9.81 m/s 3. The attempt at a solution I don't know how to solve it. All the information you are given is theta = 42 and the X distance is 53 m, I don't see how you can use any of those equations to solve for anything with only those two pieces of information.