Projectile motion snowball help

Click For Summary
SUMMARY

The discussion focuses on solving projectile motion problems involving a snowball rolling off a barn roof at a 40-degree angle with an initial speed of 7 m/s. The calculations reveal that the snowball strikes the ground 11.792 meters from the edge of the barn. For the second part of the problem, the correct approach involves determining the vertical displacement at a horizontal distance of 4 meters to assess whether a man standing 1.9 meters tall will be hit by the snowball. Key corrections include using a negative initial vertical velocity and recognizing that vertical displacement can be defined from either the roof or the ground level.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Knowledge of trigonometric functions for resolving components
  • Ability to solve quadratic equations
NEXT STEPS
  • Study the derivation of kinematic equations in projectile motion
  • Learn how to apply trigonometric functions in physics problems
  • Practice solving projectile motion problems with varying angles and initial speeds
  • Explore the impact of different coordinate systems on motion analysis
USEFUL FOR

Students studying physics, educators teaching projectile motion concepts, and anyone interested in applying kinematic equations to real-world scenarios.

imAwinner
Messages
10
Reaction score
0
[SOLVED] Projectile motion help

A snowball rolls of a barn roof that slopes downward at an angle of 40 degrees. The edge of the roof is 14 m above the ground, and the snowball has a speed of 7 m/s as it rolls off the roof.

a) How far from the edge of the barn does the snowball strike the ground if it doesn't strike anything else while falling?

b) A man 1.9 m tall is standing 4 m from the edge of the barn, will he be hit by the snowball?

My answer is 11.792 m for (a)

x
a=0
v=7cos40=5.36
x=5.36t


y
a=-9.8
v=7sin40-9.8t= 4.5-9.8t
y=4.5t-4.9t^2+14 (is this right?)

When y=0 : 0=-4.9t^2 + 4.5t + 14 (use quadratic equation)
t=2.2
Plug it into x equation: x=5.36(2.2)
x=11.792 m

Now for (b) i don't know what to do. I said x=4 and got t=.746 s
Then I plugged it into the y equation but my answer turned out to be 14.36 which is impossible. Any help is greatly appreciated.
 
Last edited:
Physics news on Phys.org
Your equation for x-axis is correct. However, in the equations along y axis, the initial velocity should be with -ve sign (-4.5 m/s) because it is downward (same reason acceleration g is -ve). As the snowball hits the ground, vertical displacement is -14m (note the -ve sign). Put y=-14 in the second equation and solve for t. Put this value of t in the equation for x to obtain the required distance from the edge of the barn.

To find answer to b) : Determine the time instant when horizontal displacement is 4m. Then determine the vertical displacement (from the top) at that instant. Determine height of the snowball from ground. That will answer b).
 
Vijay Bhatnagar said:
Your equation for x-axis is correct. However, in the equations along y axis, the initial velocity should be with -ve sign (-4.5 m/s) because it is downward (same reason acceleration g is -ve). As the snowball hits the ground, vertical displacement is -14m (note the -ve sign). Put y=-14 in the second equation and solve for t. Put this value of t in the equation for x to obtain the required distance from the edge of the barn.

To find answer to b) : Determine the time instant when horizontal displacement is 4m. Then determine the vertical displacement (from the top) at that instant. Determine height of the snowball from ground. That will answer b).

Thank you but shouldn't y still equal zero because the y and x-axis is on the bottom of the barn not the roof; even though its traveling negative it hits at zero, not -14?

Never mind, its the same thing. Thank you so much!
 
Last edited:
The choice of the origin is optional. You could take the top point as y=0 or the ground as y=0. In the first case initial displacement will be 0 and final displacement -14m. In the second case initial and final displacements will be +14m and 0 respectively. All equations for y-axis will written accordingly.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
2K
Replies
15
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
5
Views
3K
Replies
9
Views
5K
  • · Replies 4 ·
Replies
4
Views
5K
Replies
25
Views
3K