1. The problem statement, all variables and given/known data A moderate wind accelerates a pebble over a horizontal xy plane with a constant acceleration a = (6i + 7j)m/s^2 . At time t = 0, the velocity is (3i)m/s . What are the (a) magnitude and (b) angle of its velocity when it has been displaced by 12.0 m parallel to the x axis? i= acceleration in x component , j = acceleration in y component 3. The attempt at a solution vx^2 = (3m/s)^2 + 2 (6m/s^2) (12m/s) vx^2= 9m/s + 144m/s vx = 12.36 I did that and got velocity wrong what do I do?