- #1
soul5
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Homework Statement
A moderate wind accelerates a pebble over a horizontal xy plane with a constant acceleration a = (6i + 7j)m/s^2 . At time t = 0, the velocity is (3i)m/s . What are the (a) magnitude and (b) angle of its velocity when it has been displaced by 12.0 m parallel to the x axis?
i= acceleration in x component , j = acceleration in y component
The Attempt at a Solution
vx^2 = (3m/s)^2 + 2 (6m/s^2) (12m/s)
vx^2= 9m/s + 144m/s
vx = 12.36
I did that and got velocity wrong what do I do?