Projectile Motion XY Plane: Solving for Height & Time

In summary, the conversation discusses a ball being tossed from a building with an initial velocity of 8.00 m/s at an angle of 20 degrees below the horizontal. It takes 3.00 seconds for the ball to strike the ground and the question asks for the horizontal distance, height, and time at a certain point. The solution for part (a) is found to be 22.5m using kinematic equations, but part (b) and (c) require additional calculations using the equations h = Vx*t + 1/2*g*t^2 and Vxf^2 = Vxi^2 + 2*g*h.
  • #1
philok
8
0

Homework Statement



A ball is tossed from a building. The ball is given an intial velocity of 8.00 m/s at an angle of 20 degrees below the horizontal. It strikes the ground 3.00s later.
a) how far horizontally from the base of the building does the ball strike the ground?
b) Find the height from which the ball was thrown.
c) How long does it take the ball to reach a point 10m below the level of launching

Homework Equations


Kinematic equations.


The Attempt at a Solution


I solved part a with no problem. 22.5m. However, I can't come up with the others using the kinematics or trig. I am missing something somewhere.
The vel in the x direction is 7.5m/s and the vel in the y is 2.74 m/s.
Thats all i got.
 
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  • #2
For (b) use
h = Vx*t + 1/2*g*t^2
For (c)
Vxf^2 =Vxi^2 + 2*g*h'
 
  • #3
ok got b). How can I use that equation for c) when it is asking for time?
 
  • #4
h = Vx*t + 1/2*g*t^2
Use the above formula and put h = 10 m and solve for t.
 

1. What is projectile motion in the XY plane?

Projectile motion in the XY plane is the movement of an object through space under the influence of gravity, with no other external forces acting upon it. The object moves along a curved path, known as a parabola, with its motion in the horizontal and vertical directions being independent of each other.

2. How do you calculate the height of a projectile in the XY plane?

The height of a projectile in the XY plane can be calculated using the formula h = vy² / 2g, where h is the height, vy is the vertical component of velocity, and g is the acceleration due to gravity. This formula assumes that the object is launched from ground level and lands at the same height.

3. What is the time of flight for a projectile in the XY plane?

The time of flight for a projectile in the XY plane can be calculated using the formula t = 2vy / g, where t is the time of flight, vy is the vertical component of velocity, and g is the acceleration due to gravity. This formula assumes that the object is launched from ground level and lands at the same height.

4. How does the angle of launch affect the height and time of a projectile in the XY plane?

The angle of launch affects the height and time of a projectile in the XY plane because it determines the initial velocity and direction of the object. A higher angle of launch will result in a longer time of flight and a greater height, while a lower angle of launch will result in a shorter time of flight and a lower height.

5. What are some real-world applications of projectile motion in the XY plane?

Projectile motion in the XY plane has many real-world applications, such as in sports like baseball and golf, where the trajectory of a ball is affected by gravity. It is also used in military and defense systems to calculate the trajectory of missiles and projectiles. Additionally, it is used in physics experiments to study the effects of gravity on objects in motion.

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