Solving Projectiles Problem: Ball Rolls Horizontally Off Stairway

In summary, the conversation discusses a problem involving a ball rolling off the top of a stairway with a given speed and the goal is to determine which step the ball hits first. The individual attempts to solve the problem using equations and explains their thought process. Another person gives a suggestion to consider the time it takes for the ball to fall the height of the first step and the horizontal distance it travels in that time. The conversation ends with the individual realizing their mistake and thanking the other person for their help.
  • #1
NooDota
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Homework Statement


A ball rolls horizontally off the top of a stairway with
a speed of 1.52 m/s. The steps are 20.3 cm high and 20.3 cm wide.
Which step does the ball hit first?

Homework Equations

The Attempt at a Solution



The book says it's the third step.

I tried, using equations:

x-x0=V0*Cos(theta0)*t

y-y0 = -1/2*g*t^2

Where x0 and y0 are both 0

x and y are both either 1 * 20.3 * 10^-2 or 2 * 20.3 * 10^-2 or 3 * 20.3 * 10^-2 etc...

And see where the time in the two equations would be equal. It wasn't the same time for the third step (3*20.3)

I got t=0.4 for the x part of the motion
and t=0.35 for the y part of the motionWhat am I doing wrong?
 
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  • #2
Draw a picture of the steps in profile.

Check the time it takes the ball to fall the height of the first step. In that same amount of time, will the ball travel horizontally more or less distance than the step is wide?

If it's a greater horizontal distance than the step is wide, rinse and repeat the calculation above until the ball hits a step.
 
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  • #3
NooDota said:

Homework Statement


A ball rolls horizontally off the top of a stairway with
a speed of 1.52 m/s. The steps are 20.3 cm high and 20.3 cm wide.
Which step does the ball hit first?

Homework Equations

The Attempt at a Solution



The book says it's the third step.

I tried, using equations:

x-x0=V0*Cos(theta0)*t

y-y0 = -1/2*g*t^2

Where x0 and y0 are both 0

x and y are both either 1 * 20.3 * 10^-2 or 2 * 20.3 * 10^-2 or 3 * 20.3 * 10^-2 etc...

And see where the time in the two equations would be equal. It wasn't the same time for the third step (3*20.3)

I got t=0.4 for the x part of the motion
and t=0.35 for the y part of the motionWhat am I doing wrong?
You are assuming that the ball hits at the very end of the step. It doesn't.
 
  • #4
Thanks.
 

1. How do you determine the initial velocity of the ball?

The initial velocity of the ball can be determined by using the equation v = d/t, where v is the velocity, d is the distance traveled, and t is the time it takes for the ball to travel that distance. You can also use the Pythagorean Theorem to calculate the initial velocity if you know the height and horizontal distance of the stairway.

2. How do you calculate the time it takes for the ball to reach the ground?

The time it takes for the ball to reach the ground can be calculated using the equation t = √(2h/g), where t is the time, h is the height of the stairway, and g is the acceleration due to gravity (9.8 m/s²). This equation assumes that the ball is being launched horizontally from the top of the stairway.

3. What factors affect the trajectory of the ball?

The trajectory of the ball is affected by several factors, such as the initial velocity, angle of launch, air resistance, and the force of gravity. These factors can be manipulated to change the path of the ball.

4. How do you determine the angle of launch for the ball?

The angle of launch can be determined using the equation θ = tan⁻¹(vy/vx), where θ is the angle of launch, vy is the vertical component of the initial velocity, and vx is the horizontal component of the initial velocity. This angle will determine the direction in which the ball will travel.

5. What is the maximum height the ball will reach?

The maximum height the ball will reach can be calculated using the equation h = v²sin²θ/2g, where h is the maximum height, v is the initial velocity, θ is the angle of launch, and g is the acceleration due to gravity. This equation assumes that the ball is being launched horizontally from the top of the stairway.

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