Projection of a triangle in XY plane

farmd684
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Homework Statement



triangle in the plane z=1/2y with vertices (2,0,0) (0,2,1) (0,0,0)

please help me to find out the projection of the triangle in xy plane.

thanks

Homework Equations





The Attempt at a Solution

 
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The projection of (x,y,z) into the xy plane is (x,y). It's a lot more simple than you think.
 
Dick said:
The projection of (x,y,z) into the xy plane is (x,y). It's a lot more simple than you think.

Thanks a lot :biggrin:
 

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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