Proof Annihilator: W1 & W2 Intersection | W1 & W2 Annihilator

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Let W1 and W2 be subspaces of a finite dimension.
Prove that A(W1 intersection with W2) = A(W1) + A(W2)
Where A(W1) is the annihilator of W1.
I can prove one way, but not the other. How do I prove the rhs is contained in the lhs?
 
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Try to find the dimension of A(W1) + A(W2) and A(W1 intersect. W2) to show that they are the same space.
It will help to show that [A(W1) intersect. A(W2)] = A(W1 + W2)
 
If you have an operator 'a' that vanishes on W1 intersect W2, then you have have to construct two operators a1 in A(W1) and a2 in A(W2) such that a=a1+a2. I'd suggest you pick an appropriate basis for W1+W2.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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