Proof by Induction: Understanding D/dx Formula

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The discussion revolves around the formula for the nth derivative of 1/x^2, expressed as d^n/dx^n 1/x^2 = (-1)^n * (1+n)! * x^-(n+2). A participant seeks clarification on how to differentiate this expression, particularly how the term (-k-1) appears in their textbook's example. The essence of proof by induction is highlighted, emphasizing the need to establish a base case and demonstrate that if the statement holds for n=k, it also holds for n=k+1. Participants suggest revisiting derivative rules, specifically the power rule, to understand the differentiation process better. The conversation underscores the challenge of grasping the transition between terms in derivative calculations.
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Ok so I have found a formula for d^n/dx^n 1/x^2
= (-1)^n * (1+n)! * x^-(n+2)

So I have to do d/dx [(-1)^n * (1+n)! * x^-(n+2)] and see what I end up with. But how do I do that.

My book gives an example: (from d/dx (1+x)^-1)
d/dx [(-1)^k * k!(1+x)^(-k-1)] = (-1)^k * k!(-k-1)(1+x)^(-k-2)=...

What on Earth is going on?! My book just drops explaning _how_ . Where does (-k-1) come from? I'm stuck...

Thanks
 
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sony said:
Ok so I have found a formula for d^n/dx^n 1/x^2
= (-1)^n * (1+n)! * x^-(n+2)

So I have to do d/dx [(-1)^n * (1+n)! * x^-(n+2)] and see what I end up with. But how do I do that.

My book gives an example: (from d/dx (1+x)^-1)
d/dx [(-1)^k * k!(1+x)^(-k-1)] = (-1)^k * k!(-k-1)(1+x)^(-k-2)=...

What on Earth is going on?! My book just drops explaning _how_ . Where does (-k-1) come from? I'm stuck...

Thanks


the essence of proof by induction is to show that

a) there is a minimum case where what you want to prove is true
b) that if n=k is true, it follows automatically (after some manipulation) that n=k+1 is true.

there is a theorem that says that if these conditions are satisfied, the statement in question is true.


so the authors are trying to show that n=k implies that n=k+1.
 
Brad Barker said:
the essence of proof by induction is to show that

a) there is a minimum case where what you want to prove is true
b) that if n=k is true, it follows automatically (after some manipulation) that n=k+1 is true.

there is a theorem that says that if these conditions are satisfied, the statement in question is true.


so the authors are trying to show that n=k implies that n=k+1.
Yes I get _that_ :)

But how do I do the derivative of that expression?
 
sony said:
Ok so I have found a formula for d^n/dx^n 1/x^2
= (-1)^n * (1+n)! * x^-(n+2)

So I have to do d/dx [(-1)^n * (1+n)! * x^-(n+2)] and see what I end up with. But how do I do that.

Reread the chapter on derivatives. (d/dx)(x^n) = n*x^(n-1).
 
Nevermind, it was how to get from (-1)^k to (-1)^k+1 and the faculty thing I didnt get.
 
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