Proof of Continuity of f+g & f*g on R

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SUMMARY

This discussion addresses the existence of nowhere continuous functions f and g, specifically the Dirichlet function D(x), such that their sum f + g is continuous on R, and their product f * g is also continuous. The functions are defined as f(x) = 1 - D(x) and g(x) = D(x). The sum simplifies to (f + g)(x) = 1, which is continuous, while the product (f * g)(x) = D(x) - D(x)^2 requires further analysis of the Dirichlet function's behavior at rational and irrational points.

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  • Understanding of the Dirichlet function D(x)
  • Knowledge of continuity in real analysis
  • Familiarity with limits and convergence concepts
  • Basic algebraic manipulation of functions
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Homework Statement



Show that there exist nowhere continuous functions f and g whose sum f+g is continuous on R. Show that the same is true for their product.

Homework Equations



None

The Attempt at a Solution



Let f(x) = 1-D(x), where D(x) is the Dirichlet function
Let g(x) = D(x)

(f+g)(x) = 1

(f*g)(x) = D(x) - D(x)^2 <-- where I'm befuddled

I know that D(x) can be written as the limit of cos(m!*pi*x)^(2n) as n, m --> infinity and that D(x)^2 is then equal to cos(m!*pi*x)^(4n). Since n --> infinity, are D(x) and D(x)^2 equivalent?
 
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Write out the definitions of f(x) and g(x) in terms of x and look at their product.
 
LCKurtz said:
Write out the definitions of f(x) and g(x) in terms of x and look at their product.

You mean it will alternate between 0^2 and 1^2 then?
 
ƒ(x) said:
You mean it will alternate between 0^2 and 1^2 then?

No. I mean if x is rational what are f(x) and g(x) and their product. And what if x is irrational?
 

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