Proof that a function composition is differentiable

Hernaner28
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Homework Statement


Let f:R->R, differentiable, f(1)=1 and f'(1)=2.

Homework Equations


Prove that g:R->R such that g(x)=f(x)Arctg(f(x)) is differentiable in x=1 and calculate g'(1)

The Attempt at a Solution


I would prove it saying that if a function is differentiable then the product and composition it's differentiable, but I don't think is that simple, am I wrong?

Thanks!
 
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Hernaner28 said:

Homework Statement


Let f:R->R, differentiable, f(1)=1 and f'(1)=2.


Homework Equations


Prove that g:R->R such that g(x)=f(x)Arctg(f(x)) is differentiable in x=1 and calculate g'(1)


The Attempt at a Solution


I would prove it saying that if a function is differentiable then the product and composition it's differentiable, but I don't think is that simple, am I wrong?

Thanks!
It does appear to be that simple, so I suppose that means, that you are wrong about it not being that simple.

Now, calculate g'(1) .
 
Thanks! ;)
 
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