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Proof using f(x1,y1)f(x0,y0)=fx(x*,y*)(x1x0)+fy(x*,y*)(y1y0)
 Similar Discussions: Proof using f(x1,y1)f(x0,y0)=fx(x*,y*)(x1x0)+fy(x*,y*)(y1y0)

Partial derivatives, why is the fy this? (Replies: 2)
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