1. The problem statement, all variables and given/known data(adsbygoogle = window.adsbygoogle || []).push({});

A proton traveling at a speed of 7.22 *106m/s enter the gap between the plates of a 7.86 cm wide parallel plate capacitor. The surface charge densities on the plate are ± 4.98 *10-6 C/m2. How far (in m) has the proton deflected sideways when it reaches the far edge of the capacitor? Assume that the electric field is uniform inside the capacitor and zero outside.

2. Relevant equations

S= (1/2)*(E*q)/m*(d/v)^2?

3. The attempt at a solution

I just don't know what goes where or if I even have the right formula. Im truthfully lost. A classmate told me to use the above formula but didnt explain it. I got the concept he explained but lost the math. so what formula and how does it fit together?

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# Homework Help: Proton in a plate capacitor: how far does it go?

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