Proton speed needed to circle the earth

AI Thread Summary
To determine the speed a proton needs to circle the Earth at an altitude of 1550.0 km above the magnetic equator, the relevant magnetic field intensity is 4.19 × 10−8 T. The radius for the proton's path is calculated by adding the Earth's radius to the given altitude. The equation r = m*v/Q*B is used to solve for the velocity (v) of the proton. The discussion indicates that the initial calculations are on the right track, but confirmation of the approach is sought. Proper application of the formulas will yield the required speed in meters per second.
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Homework Statement



Assume that Earth’s magnetic field is every-
where perpendicular to the path of a proton
and that Earth’s magnetic field has an inten-
sity of 4.19 × 10−8 T.
What speed would a proton need to achieve
in order to circle Earth 1550.0 km above the
magnetic equator?
Answer in units of m/s.



Homework Equations



r=m*v/Q*B
r=(r Earth + r given in the question )

The Attempt at a Solution



i solved for v but I am not sure if what I am doing is correct
 
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You are in right track.
 
thanX
 
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