Prove 3 distinct points lying on the some curve

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To prove that three distinct points (p1, q1), (p2, q2), and (p3, q3) lie on a quadratic curve defined by the equation y = a + bx + cx², one can set up a system of linear equations based on these points. Each point provides an equation that relates the coefficients a, b, and c to the x and y coordinates of the points. This system can be represented in matrix form, allowing for the application of matrix methods to solve for the coefficients. The discussion clarifies that the correct form of the equations involves the square of p, ensuring the quadratic relationship is maintained. Ultimately, the three points can indeed be shown to lie on a quadratic curve by solving this system.
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Homework Statement



Given points (p1, q1), (p2, q2), (p3, q3) in the plane with p1, p2, p3 distinct, show that they lie on some curve with equation y = a + bx + cx2.

It should be related to matrix but I have no idea about this question. Could anyone help? Thanks!

Homework Equations





The Attempt at a Solution

 
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One way to examine this question is given these three point you could find out, what a,b, and c is satisfied for this equation. So you know that:
<br /> \begin{array}{ccc}<br /> q_{1} &amp; = &amp; ap_{1}+bp_{1}+cp_{1} \\<br /> q_{2} &amp; = &amp; ap_{2}+bp_{2}+cp_{2} \\<br /> q_{3} &amp; = &amp; ap_{3}+bp_{3}+cp_{3} <br /> \end{array}<br />
This is a system of linear equations with unknowns a,b and c, the system can be solved via matrix methods.
 
Thanks for your help!
But I don't understand how the equation y = a + bx +cx2 can be transformed into the form y = ax + bx + cx
 
Because it can't. I made a typo, sorry! The equations should read:
<br /> \begin{array}{ccc}<br /> q_{1} &amp; = &amp; ap_{1}+bp_{1}+cp_{1}^{2} \\<br /> q_{2} &amp; = &amp; ap_{2}+bp_{2}+cp_{2}^{2} \\<br /> q_{3} &amp; = &amp; ap_{3}+bp_{3}+cp_{3}^{2} <br /> \end{array}<br />

Mat
 
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