Prove an infinite sum exists and its sum

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Homework Statement


Let {b k } be a sequence of positive numbers. Assume that there exists a sequence {a k}, such that a k is greater than or equal to 0 for all k, a_k is decreasing, the limit of a_k is 0 and b_k = a_k - a _(k+1). Show that the sum from k=1 to infinity of b k exists and equals a_1

Homework Equations


Not really any I can think of

The Attempt at a Solution


I'm not sure how to prove this. The sum of b_k has two parts that both go to zero, but I can think of an a_k that satisfies all those properties but doesn't converge (1/k), but if you write out the sum you can clearly see all the terms cancel except the a_1 term.

For example:

Sum of b_k = (a1 - a 2 ) + (a_2-a_3)+(a_3-a_4)+...

Which clearly cancels all the terms except a_1. But this doesn't seem rigoruous enough.(Also sorry for inconsistent subscripts, I'm on my phone)
 
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I would start by doing just what you did. Compute the partial sum,
##\sum_{i=1}^{N-1} b_k##
Then show that in the limit as N goes to infinity, you get what you expect.
 
B3NR4Y said:

Homework Statement


Let {b k } be a sequence of positive numbers. Assume that there exists a sequence {a k}, such that a k is greater than or equal to 0 for all k, a_k is decreasing, the limit of a_k is 0 and b_k = a_k - a _(k+1). Show that the sum from k=1 to infinity of b k exists and equals a_1

Homework Equations


Not really any I can think of

The Attempt at a Solution


I'm not sure how to prove this. The sum of b_k has two parts that both go to zero, but I can think of an a_k that satisfies all those properties but doesn't converge (1/k), but if you write out the sum you can clearly see all the terms cancel except the a_1 term.

For example:

Sum of b_k = (a1 - a 2 ) + (a_2-a_3)+(a_3-a_4)+...

Which clearly cancels all the terms except a_1. But this doesn't seem rigoruous enough.(Also sorry for inconsistent subscripts, I'm on my phone)

Don't forget that the infinite sum ##\sum_{i=1}^{\infty} b_i ## is defined as the limit ##\lim_{n \to \infty} \sum_{i=1}^n b_i##. That is, the infinite sum exists if and only if the limit of finite sums exist.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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