Prove F is a field where F maps to itself

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Hello, I am not exactly sure how to go about proving a a Field with given properties is a field.
Any help would be appreciated. At least a push in the right direction/

Homework Statement


http://www.upload.mn/view/q77nuboss6set86gbhfs.jpg


Homework Equations





The Attempt at a Solution

 
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Probably by showing it satisfies the field axioms...

it's tough to be more specific without knowing what properties you're talking about
 
First you say F "maps to itself" which makes no sense. Then you say "prove that a field is a field"!

In fact, the problem you posted says neither of those. It says:

If \phi is an isomorphism from a field F to itself, and F_\phi is defined as {x| \phi(x)= x}, in other words, the set of all member of F that \phi does not change, prove that F_\phi is a field.

Office Shredder told you how to do that: what are the "axioms" or requirements for a field?
 
Obviously I did not understand the problem in its entirety . I believe I understand it now, and thanks to your assistance.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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