Prove Metric Space: d_p Not Metric when p < 1

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Homework Statement



Let X = \mathbb{R}^n be equipped with the metric
<br /> d_p(\boldsymbol{x}, \boldsymbol{y}) := \left[ \sum^n_{i=1} |x_i<br /> - y_i|^p \right]^{\frac{1}{p}}, p \geq 1<br />

Homework Equations



Show that if p &lt; 1 then d_p is not a metric.

The Attempt at a Solution



I don't know what approach I should take. The textbooks have proofs showing that when p \geq 1 the function d_p is a metric but only uses p in the equation \displaystyle \frac{1}{p} + \frac{1}{q} = 1. Can someone give me a hint where I should start?
 
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Trying specific examples is often useful.
 
I still can't figure out. Can you give me more hint?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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