Prove that the Bohr hydrogen atom approaches classical conditions when [..]

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SUMMARY

The discussion centers on the Bohr model of the hydrogen atom and its transition to classical conditions. Key equations include energy levels E_k = chR/(n_k)^2 and E_l = chR/(n_l)^2, with ΔE = hc/λ representing the energy difference related to photon emission. Participants debate the presence of a negative sign in energy calculations and its implications for photon energy. The conversation emphasizes the relationship between frequency, wavelength, and the speed of light (c), concluding that understanding these relationships is crucial for accurate calculations in quantum mechanics.

PREREQUISITES
  • Understanding of the Bohr model of the hydrogen atom
  • Familiarity with quantum mechanics terminology
  • Knowledge of energy level equations in atomic physics
  • Basic grasp of the relationship between frequency, wavelength, and the speed of light (c)
NEXT STEPS
  • Study the derivation of the Bohr model equations for hydrogen
  • Learn about the implications of negative energy levels in quantum mechanics
  • Explore the concept of photon energy and its relationship to emitted frequencies
  • Investigate classical versus quantum mechanical interpretations of atomic behavior
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Students of physics, particularly those focusing on quantum mechanics, educators teaching atomic theory, and researchers exploring the transition from classical to quantum models in atomic physics.

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"Prove that the Bohr hydrogen atom approaches classical conditions when [. . .]"

Homework Statement


The problem and its solution are attached as ProblemSolution.jpg.

Homework Equations


E_k = chR/(n_k)^2
E_l = chR/(n_l)^2
ΔE = hc/λ
hc/λ = chR[1/(n_k)^2 – 1/(n_l)^2]
1/ λ = R[1/(n_k)^2 – 1/(n_l)^2]


The Attempt at a Solution


Given E_k = chR/(n_k)^2 and E_l = chR/(n_l)^2,

ΔE = chR[1/(n_k)^2 – 1/(n_l)^2]

Therefore, since, ΔE = hc/λ,

hc/λ = chR[1/(n_k)^2 – 1/(n_l)^2]
1/ λ = R[1/(n_k)^2 – 1/(n_l)^2]
1/ λ = R[1/(n_k)^2 – 1/(n_l)^2]
1/ λ = R[1/(n_k)^2 – 1/(n_l)^2
ν = R[(n_l)^2 – (n_k)^2]/[(n_k)^2 * (n_l)^2]

and, n_l – n_k = -1 which counters the negative that I had initially compared to the answer of the book so far and now the only difference is that my answer lacks the c multiplicative factor that the book has. If I did something wrong, what is it? Or is it the book?

Also, how is the “crazier” part of equation (1.6.3) obtained?

If more information is needed, just ask.

Any help would be greatly appreciated!
Thanks in advance!
 

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s3a said:
my answer lacks the c multiplicative factor that the book has. If I did something wrong, what is it? Or is it the book?

What is the relationship between frequency, wavelength, and c?

Also, how is the “crazier” part of equation (1.6.3) obtained?

Just substitute the well-known Bohr model expressions for the radius of the orbit and the speed of the electron in the orbit.
 


1) The relationship between frequency, wavelength, and c is v = c/λ.

2) I found the equation for the radius “on a silver-platter” and derived the equation for the velocity and yes, plugging them in worked. :smile:

3) Now, I still have some work which disagrees with the solution and it is attached as MyWork.jpg. Could you please tell me if I am wrong or if it's the solution that is wrong as well as what as what to do to get the correct answer if I am wrong?
 

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S3a, The energy levels are negative: E = -chR/n2. The text that you quoted in your original post left out the minus sign for some reason (misprint?)
 


Could it be that the negative sign is to indicate that the (light) energy is being lost from the Hydrogen orbital whereas here we are talking about the energy gained by the photon?

I deduced this based on the following quote from the screen-shot of the problem and its solution that I attached initially.: "Therefore the frequency of the emitted photon is [. . .]". The fact that that equation is the frequency of the emitted photon should imply that the frequency multiplied by h (plank's constant) is the energy of the emitted photon gained (rather than that lost from the Hydrogen orbital).

That would explain why the book has it the way it does but not why I get the book's answer multiplied by -1. Is there something with my logic above that doesn't hold?
 


To me the natural way to think about it is that the energy of the photon equals the loss of energy of the atom as the atom goes from the higher excited state (nk) to the lower excited state (nl).

Thus h\nu = Ek - El where Ek = -chR/nk2 and El = -chR/nl2
 


Long before the Bohr model was developed, it was known that the frequencies of hydrogen could be calculated by taking the difference of numbers of the form cR/n2 where n is a positive integer and R was an empirically determined number. These numbers cR/n2 were called "terms".

The Bohr model later explained this numerology by showing that the energy levels of hydrogen were just the negative of these terms multiplied by h and the model derived the value of R in terms of fundamental constants.

Maybe your book is using these "terms" rather than energy levels of the atom.
 
Last edited:


What you said earlier makes sense but could it also be the case that it just doesn't matter what the sign is because what the question asks for ultimately is frequency and we just want to compare the magnitudes of the two frequencies (classical and modern) so we take the absolute value? Is that a valid thought process?
 


s3a said:
What you said earlier makes sense but could it also be the case that it just doesn't matter what the sign is because what the question asks for ultimately is frequency and we just want to compare the magnitudes of the two frequencies (classical and modern) so we take the absolute value? Is that a valid thought process?

That sounds good to me. :smile:
 
  • #10


Okay, thanks for all your help! :smile:
 

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