Bradyns
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Prove:
\frac{CosθSinθ}{1 + Tanθ} = Cos2θ
===========================
I multiply out the denominator to get:
CosθSinθ = Cos2θ + CosθSinθ
I cannot seem to prove it.
Starting to think it's a trick question.. :/
\frac{CosθSinθ}{1 + Tanθ} = Cos2θ
===========================
I multiply out the denominator to get:
CosθSinθ = Cos2θ + CosθSinθ
I cannot seem to prove it.
Starting to think it's a trick question.. :/