Proving (A X B) X C = AxBxCx (i x k) + AyBxCy (j x k) | Unit Vectors

AI Thread Summary
The discussion focuses on proving the vector identity (A X B) X C = AxBxCx (i x k) + AyBxCy (j x k), where A, B, and C are vectors expressed in terms of unit vectors i, j, and k. An attempt at a solution involves applying the vector triple product identity, leading to a simplification that reveals a discrepancy when specific values are substituted. The left-hand side produces a non-zero vector while the right-hand side evaluates to zero under certain conditions, indicating a potential flaw in the proposed identity. Participants suggest that using three-dimensional representations for A and B may help resolve the issue. The conversation highlights the complexity of vector identities and the importance of careful vector representation in proofs.
abrowaqas
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Homework Statement


Prove that
(A X B) X C = AxBxCx (i x k) + AyBxCy (j x k)
where i , j and k are unit vectors ?


Homework Equations





The Attempt at a Solution



let A= Axi+Ayj
B= Bxi+Byj

L.H.S = (AXB)XC
= (C.A) B - (C.B) A
= (AxCx+AyCy)(Bxi+Byj)- (BxCx+ByCy)(Axi+Ayj)
after simplification we get
= AxByCx i - AxByCy j + AyBxCy i - AyBxCx j
there i am held up... now how i proceed further..
 
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I believe you should start by writing A and B has 3 dimensional vectors rather than 2. I would follow the exact steps you have above and then finish the problem by expanding the RHS (AxBxCx (i x k) + AyBxCy (j x k)) and showing that the two are equivalent.
 
abrowaqas said:

Homework Statement


Prove that
(A X B) X C = AxBxCx (i x k) + AyBxCy (j x k)
where i , j and k are unit vectors ?
It doesn't work for A=i, B=j, and C=i. Since Bx=0, the righthand side is equal to 0, but the lefthand side is equal to j.
 
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