Proving arcsin(somevalue) = 2arctan(rootx) - value

[montana111]

Homework Statement

prove the identity:

arcsin( x-1/x+1 ) = 2 * arctan( sqrt(x) ) - pi/2

Homework Equations

if f'x = g'x for all x in an interval (a,b) then f - g is constant on (a,b); that is, fx = gx + c where c is constant.

this material above is in the same section as rolles thm and the mean value thm if that helps at all.

The Attempt at a Solution

Im assuming that i use arcsin(value) as fx and 2arctan(value) as gx and verify that their derivatives are equal, however i can't seem to do this. this is what i got... :

d/dx arcsin( x-1/x+1 ) = 1/( sqrt( 1 - ( x-1/x+1 )^2 ) ) * ( x+1 - x-1 / ( x+1 )^2

and

d/dx 2arctan(sqrt( x) ) = 2/(1+ sqrt(x^2)) * 1/(2 * sqrt(x)) = 2/(1+x) * 1/(2 * sqrt(x) )

my real questions here is what are the real derivatives of these two functions and can someone please right down the solution to that explicitly so i am not confused, THANK YOU PHYSICS FORUMS MEMBERS.

 

[Mark44]

Homework Statement

prove the identity:

arcsin( x-1/x+1 ) = 2 * arctan( sqrt(x) ) - pi/2

Homework Equations

if f'x = g'x for all x in an interval (a,b) then f - g is constant on (a,b); that is, fx = gx + c where c is constant.

this material above is in the same section as rolles thm and the mean value thm if that helps at all.

The Attempt at a Solution

Im assuming that i use arcsin(value) as fx and 2arctan(value) as gx and verify that their derivatives are equal, however i can't seem to do this. this is what i got... :

d/dx arcsin( x-1/x+1 ) = 1/( sqrt( 1 - ( x-1/x+1 )^2 ) ) * ( x+1 - x-1 / ( x+1 )^2

You didn't get the chain rule part quite right in the work above.
d/dx arcsin( x-1/x+1 ) = 1/( sqrt( 1 - ( x-1/x+1 )^2 ) ) * ( x+1 - x+1) / ( x+1 )^2
I fixed an incorrect sign right here --------------------------------^
There's a lot of simplification that you can do, to get it to 1/(sqrt(x) * (x + 1)), which is the same as what you get in the next part.

and

d/dx 2arctan(sqrt( x) ) = 2/(1+ sqrt(x^2)) * 1/(2 * sqrt(x)) = 2/(1+x) * 1/(2 * sqrt(x) )

my real questions here is what are the real derivatives of these two functions and can someone please right down the solution to that explicitly so i am not confused, THANK YOU PHYSICS FORUMS MEMBERS.