Proving Contraction Mapping: T^n is a Contraction

saraomair
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1. prove that,if T is acontraction mapping then T^n is a contraction

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The Attempt at a Solution

 
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I have absolutely no idea what you expect. This was YOUR problem, not ours. YOU are the one who has to do it. Did you not read the information that you were asked to when you registered? You must show your own attempt at solving the problem.

Start with the definition of "contraction" mapping.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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