Proving Cubic Equation Theta & a,b

  • Thread starter Thread starter agus
  • Start date Start date
  • Tags Tags
    Cubic Theta
agus
Messages
6
Reaction score
0
Hai, I have a question solving a cubic equation. I have a function
y=ax*x*x+bx*x. I want to get a solution for the value of a and b. From reference, I found that a=(xtan(Theta)-2y)/(x*x*x) and
b=(3y-xtan(Theta))/(x*x)
[Theta] is an angle or tangent of each point x along a cubic curve or function. Could anyone guide me on how to prove this statement mathematically?
TQ
 
Mathematics news on Phys.org
You want to solve for a and b but you didn't provide any conditions on them.
 
agus said:
Hai, I have a question solving a cubic equation. I have a function
y=ax*x*x+bx*x. I want to get a solution for the value of a and b. From reference, I found that a=(xtan(Theta)-2y)/(x*x*x) and
b=(3y-xtan(Theta))/(x*x)
[Theta] is an angle or tangent of each point x along a cubic curve or function. Could anyone guide me on how to prove this statement mathematically?
TQ

It is not at all clear what you want to do. Find values of a and b so that y= ax3+ bx2 has what properties??
 
Well, anyway, from what you are saying, if we can choose values of X, just let X=1, giving Y=a+b. Then use a second value. Tangent of Theta? It might help to find out what that is.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top