Proving Integral Domain of D Using Commutative Ring

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Homework Statement


Given a,b,c in D, with a not 0, we have ab=ac implies b=c. Show that the commutative ring D is an integral domain.

The Attempt at a Solution


I don't know where to begin with this.
 
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You want to show that there are no 0 divisors. Look at what's given. Look at its contrapositive.
 
So we want to assume it is not an integral domain, then show that b does not equal c?

Well, I know it is possible for b to not equal c because if we are in say, Z mod 6, then [0]=[3]=[6]. But how do I generalize this? Is this the right method to go about it?
 
You don't have to prove by contradiction. What I meant was that since we have

a \ne 0, ab = ac implies b = c,

we also know

a \ne 0, b \ne c implies ab \ne ac. Letting b = 0 or c = 0 should get you what you want.
 
I think Michael would be ashamed
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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