Proving Invertibility of A^TA with Linearly Independent Columns

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Homework Help Overview

The problem involves proving the invertibility of the matrix A^TA, where A is an m x n matrix with linearly independent columns. This falls under the subject area of linear algebra.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of the rank of A and A^TA, and some suggest considering linear combinations of columns to explore contradictions. Others propose using column operations to simplify the matrix A.

Discussion Status

The discussion is ongoing, with various approaches being explored. Some participants have offered guidance on how to think about the problem, while others are questioning the assumptions and setup.

Contextual Notes

There is a suggestion that the problem may be more appropriate for a different forum, indicating potential constraints on the audience's familiarity with the topic.

eunhye732
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Linear Algebra PLS HELP!

I need help on this problem and been trying to figure it out for awhile.
Let A be an m x n matrix with linearly independent columns. Show that A^TA is invertible.
anything will help. Thanks
 
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I assume you meant A^tA? Anyway, consider the size of that matrix to begin with, that's over half the solution right there. Ah and for future reference, maybe you should post questions like this in the other homework help forum since Linear Algebra is typically taught beyond calculus. Maybe there are some people who exclusively look in that thread to answer problems.
 
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What is the rank of A? What is the rank of A^tA?
 
I'm feeling stupid right now. Disregard my earlier suggestions--while they do work eventually, they are more trouble than they are worth. A good way to approach this problem is by considering what would happen if one of the columns of the product was a linear combination of the other columns, writing out what that would mean, and proceeding to a contradiction.
 
Disregard my earlier suggestions--while they do work eventually, they are more trouble than they are worth.
I don't think they're bad. I think you can make the problem much simpler by doing column operations to write A = A'C where C is the matrix representing the column operations, and A' is of a special form. Of course, it means you have to pick a good special form, but hey! Math is an art. :biggrin:
 
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