Proving Limit of a Sequence: Simplest Method

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Homework Statement

What is the fastest way to prove this.
1/an→1/a, where an is a sequence.

The attempt at a solution

I know how to prove this but I am looking for a simple and elegant proof.
 
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Of course, it isn't true the way you stated it. You need some hypotheses.

Elegant might mean noting that if a ≠ 0 then 1/x is continuous at a. Whether that is "simple" likely depends on the context.
 
an is a sequence. I am trying to prove this limit law for the sequence.
 
glebovg said:
an is a sequence. I am trying to prove this limit law for the sequence.

You haven't even stated the limit law correctly yet. And I thought you said you already know how to prove it. :confused:
 
I just abriviated limn→∞ an = a as an→a (as n→∞) if that is what you mean.
 
Just to be clear, you're saying that if an goes to a, you want to prove (quickly) that 1/an goes to 1/a? Correct?
 
glebovg said:
Homework Statement

What is the fastest way to prove this.
1/an→1/a, where an is a sequence.

The attempt at a solution

I know how to prove this but I am looking for a simple and elegant proof.

LCKurtz said:
You haven't even stated the limit law correctly yet. And I thought you said you already know how to prove it. :confused:

glebovg said:
I just abriviated limn→∞ an = a as an→a (as n→∞) if that is what you mean.

No, I'm not talking about notation. I'm talking about the fact that you haven't stated the theorem correctly even yet. You need something in the form

If [hypotheses here] then [conclusion here].

Your original statement, highlighted above, not only doesn't do that, it is false.
 
What do you mean it is false? How can a theorem be false? It has been proven. It is part of the Algebraic Limit Theorem.

1/an→1/a, where an is a sequence and a ≠ 0.
 
glebovg said:
1/an→1/a, where an is a sequence and a ≠ 0.

You're stating some kind of conclusion. What's the hypothesis?
 
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  • #10
LCKurtz said:
No, I'm not talking about notation. I'm talking about the fact that you haven't stated the theorem correctly even yet. You need something in the form

If [hypotheses here] then [conclusion here].

Your original statement, highlighted above, not only doesn't do that, it is false.

glebovg said:
What do you mean it is false? How can a theorem be false? It has been proven. It is part of the Algebraic Limit Theorem.

1/an→1/a, where an is a sequence and a ≠ 0.

Did you even read my post?
 
  • #11
Let lim an = a, and lim bn = b. Then, lim an/bn = a/b.
We know lim (anbn) = ab. So ...
 
  • #12
Never mind I found the neatest way to prove it.
 
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