Proving limit of the nth root of n

[Elzair]

Homework Statement

Prove the following limit:

lim_{n \rightarrow \infty } n^{ 1 / n } = 1

Homework Equations

Not sure.

The Attempt at a Solution

Given any \epsilon > 0, choose N \in \mdseries N s.t.

\left| n^{ 1 / n } - 1 \right| < \epsilon for all n > N

I am not sure how to proceed.

 

[jgens]

If you're still working on this problem and need to do it with epsilons and deltas, I think that choosing N = exp(log(1+ε)^-1) should suffice. I can't find a nice/elegant epsilon delta solution to this problem, but maybe someone else can.

 

[klondike]

Prove \lim _{n\to \infty} \sqrt[n]{n}=1.
Proof: We want:
<br /> |\sqrt[n]{n}-1|&lt;\epsilon<br />
The abs sign can be safely dropped, it follows that
<br /> n&lt;(1+\epsilon)^n<br />
Using binomial theorem to expand the first 3 terms of RHS.
<br /> n&lt;1+n\epsilon+\frac{1}{2}n(n-1)\epsilon^2+...<br />
As long as we make n<0.5n(n-1)εε, the first inequality holds. It requires
<br /> n&gt;1+\frac{2}{\epsilon^2}<br />

With all that said,
For any ε>0, there exists N=[1+2/(εε)], such that if n>N, then
<br /> |\sqrt[n]{n}-1|&lt;\epsilon<br />

Q.E.D
P.S. I love ε-δ proof:)

 

[micromass]

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