Proving Linear Dependence of 3 Vectors with 3 Unknowns

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To prove the linear dependence of the vectors a=(-1,7,-4), b=(3,5,-6), and c=(15,-1,-12), the determinant of the matrix formed by these vectors must equal zero. The discussion emphasizes that if the determinant is zero, it indicates that the vectors are linearly dependent. Alternatively, row reduction to echelon form can also demonstrate dependence by yielding a row of zeros. The user initially struggled with setting up the equations and concluded that the constants should not all be zero for dependence. Ultimately, evaluating the determinant or using row reduction are valid methods to establish linear dependence.
lo2
I have these 3 vectors. And I have to prove that they are dependent.

a=(-1,7,-4)

b=(3,5,-6)

a=(15,-1,-12)

I have tried to make 3 equtations with 3 unknows and the solve it. But I just get that the constants should be 0, what they should not be in order to prove they are dependent?
 
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So A = \begin{bmatrix}<br /> -1&amp;7&amp;4 \\<br /> <br /> \end{bmatrix}

So B = \begin{bmatrix}<br /> 3&amp;5&amp;-6 \\<br /> <br /> \end{bmatrix}

So C = \begin{bmatrix}<br /> 15&amp;-1&amp;-12 \\<br /> <br /> \end{bmatrix}

For the vectors to be linearly dependent, \left| \begin{array} {ccc} -1 &amp; 7 &amp; 4 \\ 3 &amp; 5&amp; -6 \\ 15 &amp; -1 &amp; -12 \\ \end{array} \right|= 0
 
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Alternatively, if you don't like evaluating determinants you could try row reduction to the echelon form (obtaining a final row of zeros would indicate LD).
 
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