Proving one Differentiation results to another

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Homework Statement


I need in proving that the derivative (d^{n}/dx^{n})(sin4x + cos4x) = 4n-1 cos(4x + n\pi/2)


The Attempt at a Solution


I understand implicit differentiation in basic problems but I get stump with the n exponent in the differentiation symbol; am I suppose to treat it as a 2nd, 3rd, 4th ... etc derivative?
If that's so, how should I prove that the left equation equals the right one.

So far I got to: 4(cos3x - sin3x)
 
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If you want you could try proving it by mathematical induction.

dn/dxn means the nth derivative
 
For the "induction step" you need to prove that IF
d^n 4(sin^4 x+ cos^4 x)= 4^{n-1} cos(4x+ n\pi/2)
then
d^}{n+1} 4(sin^4 x+ cos^4 x)= 4^{n} cos(4x+ (n+1)\pi/2)
You should be able to do that just by differentiating the right hand side of the first equationl.
 
Thank you, I understand now.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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