Proving PS/PQ = TX/XR in ΔPQR with Parallel Lines

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In the discussion about proving PS/PQ = TX/XR in triangle PQR with parallel lines, participants express difficulty in achieving the proof. One individual notes they can only derive PS/PQ = TX/XQ, questioning the validity of the problem. Another contributor acknowledges the challenge and appreciates the ability to tackle the question, highlighting a common struggle among high school students in geometry. The conversation emphasizes the complexity of geometric proofs involving parallel lines and triangle properties. Overall, the thread reflects a shared experience of grappling with challenging mathematical concepts.
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Homework Statement


At ΔPQR, a line is drawn parallel to QR, cuts PQ at S and PR at T. Line SR and QT intersect at X. Show that PS / PQ = TX / XR


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The Attempt at a Solution


I can not achieve that proof. The best I can get is : PS / PQ = TX / XQ. Something wrong with me or the question?
 
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I also got your result. I'm placing my bets on the faulty question :smile:
 
Mentallic said:
I also got your result. I'm placing my bets on the faulty question :smile:

OK. Thanks a bunch !
 
No worries. It's nice to see you actually know how to do this question, you have no idea how many high school students (even in year 12) getting nowhere in this kind of geometry.
 

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