Proving tensor symmetry under transformation

AI Thread Summary
The discussion focuses on proving that a second-order symmetric tensor D remains symmetric under transformation to a new coordinate system using indicial notation. The transformation law is applied, showing that D'_{pq} equals D'_{qp} by leveraging the symmetry of D and the properties of matrix transposition. The participant seeks clarification on why the indices of D swap during transposition while the transformation coefficients do not. The conclusion reached is that D'_{pq} equals D'_{qp}, confirming that the tensor remains symmetric after transformation. The inquiry highlights a need for further explanation on the transposition process.
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Homework Statement


Using indical notation, prove that a 2nd order symmetric tensor D remains symmetric when transformed into any other coordinate system.


Homework Equations


Tensor law of transformation (2nd order):
D'_{pq} = a_{pr}a_{qs}D_{rs}


The Attempt at a Solution


I think I'm required to prove that D'_{pq} = D'_{qp} (where D is a symmetric 2nd order tensor)


D'_{pq} = a_{pr}a_{qs}D_{rs}
D'^{T}_{pq} = (a_{pr}a_{qs}D_{rs})^T
D'_{qp} = a_{qs}a_{pr}D_{sr} (can someone please explain why when you transpose this, the a's swaps position but the D swaps indices?)

D_{rs} = D_{sr} (as D is symmetric)

=>D'_{pq} = a_{pr}a_{qs}D_{rs} = a_{qs}a_{pr}D_{rs} = D'_{qp}

Thus D'_{pq} = D'_{qp}


Did I prove it correctly?

Thank you
 
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