Proving the Height of Tilted P After Rotation | Triangle Method

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1. For the diagram in the attachment, prove that the height of P above floor after being tilted is h(cosb+2sinb)


2. h(cosb+2sinb)


3. I think you need to divide them up into triangles and then use the angles for each as well as maybe using a sums to products formula
 

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Let's call the bottom right point of the rectangle A, and the top left corner B, such that we are looking at rectangle OAPB.

In the rotated version, you can draw a horizontal line through A. Then, since OAP is a right angle, you can use the Z-shape in the figure to find the two subangles.
From there on it's basic geometry to find the height of B, and the difference in height between B and P.

Hopefully it is clear from the text what I meant. If not let me know, I can upload an image.
 
That sounds pretty good haha
except i don't understand where the z-shape is. Is it PA,AB and BO? and what do you mean by subangles
 
OK, here is the hint graphically.

Note the red line parallel to the horizontal line through O, and the angles marked in green.
 

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i feel stupid for asking this but what subangles should i now find
 
First of all, can you now find the height of the red line above the origin?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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