Proving the Ideal Status of K in R: I and J as Ideals in a Ring R

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Homework Statement


Let I and J be ideals in R. Is the set K = {ab|a is an element of I, b is an element of J} an ideal in R?

Homework Equations


Conditions for an ideal, I of a ring R;
(i)I is nonempty,
(ii)for any c,e ε I: c-eεI
(iii)for any c ε I, rεR: rc, cr ε I.

The Attempt at a Solution



Let a,bεK.

K is not empty since it contains 0.
K seems to satisfy condition (iii) since r(ab)=(ra)b, and raεI since I is an ideal. Then (ra)bεK.
Also, (ab)r=a(br), and since brεJ, a(br)εK.

But nothing jumps out at me when I examine ab - cd , where a,cεI and b,dεJ.

Is it possible this is not an ideal?

Thanks.
 
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Try finding a counterexample.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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