Proving the Identity: sin2(x)-sin2(x)=sin(x+y)sin(x-y)?

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Homework Statement


Prove this is an identity:
sin2(x)-sin2(x)=sin(x+y)sin(x-y)


Homework Equations


N/A


The Attempt at a Solution


I have made a lot of attempts but can not get one side to equal the other. I know It's something really simple I am missing, but can't figure it out.
 
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Clearly, you meant sin(x)^2-sin(y)^2. Use the sum formula for sin(a+b) and sin(a-b) and expand it. Then use cos^2-1=sin^2. Expand again.
 
You are correct, I did mean sin2(x) - sin 2(y). And you clearly meant 1-cos2=sin2.
Thanks.
 
Right.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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